1 (int)(long)&((struct stringpool2_t *)0)->stringpool_osf1_0, 2 (int)(long)&((struct stringpool2_t *)0)->stringpool_osf1_1, 3
1 (int)(long)&((struct stringpool2_t *)0)->stringpool_osf1_0, 2 (int)(long)&((struct stringpool2_t *)0)->stringpool_osf1_1, 3